Equivalent Concept

The number of moles of $KMn{O}_4$ That will be needed to react with one mole of sulphite ion in acidic solution is

A $50 \mathrm{gm}$ sample which may contain either ${\mathrm{H}}_2{\mathrm{SO}}_4$ or ${\mathrm{SO}}_3$ or  any combination of the two is mixed with $9 \mathrm{gm}$ of water. The maximum oleum labelling possible of the sample formed can be :

If valence factor (n-factor) of compound ${\mathrm{NaHC}}_2{\mathrm{O}}_4.2{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4.3{\mathrm{K}}_2{\mathrm{C}}_2{\mathrm{O}}_4.4{\mathrm{Al}}_2{\left({\mathrm{C}}_2{\mathrm{O}}_4\right)}_3.3{\mathrm{FeC}}_2{\mathrm{O}}_4$ in acid-base titration is $\mathrm{x}$ and redox titration with ${\mathrm{KMnO}}_4$ is $\mathrm{y}$, then $\mathrm{y}/\mathrm{x}$ is

A metallic oxide contains $53\%$ metal. The vapour density of the chloride of the metal is $66$. Find the atomic weight of the metal.

If $11.1 \mathrm{mg}$ of ${\mathrm{CaCl}}_2$ and $12 \mathrm{mg}$ of ${\mathrm{MgSO}}_4$ are present in $5 \mathrm{L}$ of water, what is its degree of hardness?

The amount of oxalic acid ($\mathrm{eq}.\mathrm{wt}.63$) required to prepare $500 \mathrm{ml}$ of its $0.10 \mathrm{N}$ solution is 

Find the equivalent weight of ${\mathrm{K}}_2{\mathrm{SO}}_4·{\mathrm{Al}}_2({\mathrm{SO}}_4{)}_3· 24{\mathrm{H}}_2\mathrm{O}$ (Mol. mass = M).

Vapour density of a metal chloride is 66. Its oxide contains 53% metal. The atomic weight of the metal is

0.36 gm of a metal was dissolved in $100 \mathrm{ml} \mathrm{of} 1 \mathrm{N} {\mathrm{H}}_2{\mathrm{SO}}_4$, and the volume of solution was made upto 1000 ml by adding water. 40 ml of this solution were neutralized completely by 28 ml of 0.1N NaOH. The equivalent mass of the metal is

Vapour density of a metal chloride is $52.5$. Calculate empirical formula of metal oxide if it contains $68\%$ metal.

$1.1 \mathrm{g} {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_{\mathrm{n}}\mathrm{COOH}$ was burnt in excess of air and the resultant gases $\left({\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}\right)$ were passed through a solution of $\mathrm{NaOH}$. The resulting solution is divided into two equal parts. One part required $75$m.e. of $\mathrm{HCl}$ for neutralisation using phenolphthalein as indicator. The other part required $100$ m.e. of $\mathrm{HCl}$ using methyl orange as indicator. Find $\mathrm{n}$.

The molarity of ${\mathrm{H}}^{+}$ ions in a solution obtained by mixing $250 \mathrm{ml}$ of $1\mathrm{N} \mathrm{HCl}$, $250 \mathrm{ml}$ of $0.5\mathrm{M} {\mathrm{H}}_2{\mathrm{SO}}_4$ and $500 \mathrm{ml}$ of $2\mathrm{M} {\mathrm{HNO}}_3$ will be $\mathrm{M}$. Then find the value of $10\mathrm{M}$.

Oxidation of ${\mathrm{K}}_4\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]$ by an oxidising agent is taking place to yield ${\mathrm{Fe}}^{3+}$, ${\mathrm{CO}}_2 \mathrm{and} {\mathrm{NO}}_3^{-}$. If the ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ is oxidising agent, then how many moles of ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ reacts with $0.6 \mathrm{mole}$ of ${\mathrm{K}}_4\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]$?

Round off the answer to the nearest integer.

Find out the normality of a solution obtained by mixing $0.45 \mathrm{N} \mathrm{KOH}$ and $0.60 \mathrm{N}$ $\mathrm{NaOH}$ in the ratio $2:1$ by volume.

Given that the oxidation number of sulphur is $-2$, the equivalent weight of sulphur is

With $4$ mole of $\mathrm{Kl}$ one mole of ${\mathrm{Cl}}_2$ is treated to yield gas, which is then treated with hypo solution, then correct regarding this is/are